Soal:
Jawaban:
H2PO4- = 0,1 M X 50mL = 5mmol
HPO4^2- = 0,2 x 100ml = 20mmol
HPO4^2- = 0,2 x 100ml = 20mmol
H+ = Ka x HA / A
= 10^-5 x 5mmol / 20mmol
= 10^-5 x 0,25
= 25 x 10^-7
pH = – log H+
= – log 25 x 10^-7
= 7 – log 25
= 7- 1,39
= 5, 61
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