Mengapa larutan HCL 0,001 m ph = 3, sama larutan CH3COOH 0,1 M ph = 3.

HCL =
H = 0,001 M = 1×10^-3 M

CH3COOH =     setiap 1 liter di jadikan 100 ml

MOL = m/v = 0,1 / 100 = 0,001
         = 0,001 = 1×10^-3 M
H = 1×10^3M

pH CH3COOH = – log 1×10^-3 = 3
pH HCL = – log 1X10^-3 = 3
jadi karena mollaritasnya sama yaitu 1×10^-3M = pH = 3