Soal:
Jawaban:
Inersia untuk bola pejal:
I = ⅖ MR²
I = ⅖ MR²
Translasi:
mg sinθ – fk = m a …..(1)
Rotasi:
fk R = I α
fk R = ⅖MR² a/R
fk = ⅖ m a … (2)
substitusi (2) ke (1)
mg sinθ – fk = m a
mg sinθ – ⅖ m a = m a
coret m
g sinθ – ⅖ a = a
g sinθ = ⁷/₅ a
a = ⁵/₇ g sinθ
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