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Jawaban:
Dik lo =1,6 m
Δl = 0,3 cm = 0,003 m
d = 0,2 cm = 0,002 m
Dit tegangan ?
jawab.
LO=πr^2 = 3,14 x 0,001^2
= 3,14 x10^-6 m
E = tegangan / regangan
= F.l / A.Δl
Δl = 0,3 cm = 0,003 m
d = 0,2 cm = 0,002 m
Dit tegangan ?
jawab.
LO=πr^2 = 3,14 x 0,001^2
= 3,14 x10^-6 m
E = tegangan / regangan
= F.l / A.Δl
tegangan = F.l0
= 1,6 F
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